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Three-terminal regulator principle
Time:2021-05-26 View:656
(1) Start the circuit
In the integrated voltage regulator, many constant current sources are often used. When the input voltage V1 is turned on, these constant current sources are difficult to conduct by themselves, so that the output voltage is difficult to establish.Therefore, a start-up circuit must be used to provide base current to the BJT T4 and T5 of the constant current source.The start-up circuit consists of T1, T2, and DZ1.When the input voltage V1 is higher than the stable voltage of the voltage regulator tube DZ1, a current flows through T1 and T2, so that the base potential of T3 rises and turns on, and the constant current sources T4 and T5 also work.The collector current of T4 passes through DZ2 to establish the normal working voltage. When DZ2 reaches the voltage regulation value equal to that of DZ1, the whole circuit enters the normal working state, and the circuit starts up.At the same time, T2 is turned off because the voltage of the emitter junction is zero, which cuts off the connection between the start-up circuit and the amplifier circuit, so as to ensure that the ripple and noise on the left side of T2 will not affect the reference voltage source.(2) Reference voltage circuit
A reference voltage circuit T4, DZ2, T3, R1, R3and D1, D2 composition, is from the reference voltage circuitwherein the stabilization voltage VZ2 of DZ2, the VBE emitter of T3, D1, D2 emitter (D1, D2 by The forward voltage value of the diode).In circuit design and process, R1, R2, DZ2 with positive temperature coefficients and T3, D1, D2 emitter junctions with negative temperature coefficients are mutually compensated, so that the reference voltage VREF basically does not change with temperature.At the same time, the constant current source is used to supply power to the voltage regulator tube DZ2, so as to ensure that the reference voltage is not affected by the fluctuation of the input voltage.
(3) Sampling comparison amplifier circuit and adjustment circuit
This part of the circuit is composed of T4~T11, in which T10, T11 form a composite adjustment tube; R12, R13 form a sampling circuit; T7, T8 and T6 form a differential amplifier circuit with a constant current source; T4, T5 form a current source as its active load.The functions of T9 and R9 are explained as follows: if there is no T9 and R9, the current IC5=IC8+IB10 of the constant current source tube T5, when the regulating tube is fully loaded, IB10 is the largest, while IC8 is the smallest; and when the load is open, IO=0, IB10 also tends to zero, at this time almost all IC5 flows into T8, which makes the variation range of IC8 large, which is not allowed for the comparison amplifier circuit. For this reason, the buffer circuit composed of T9 and R9 is connected.When IO decreases, IB10 decreases, and IC8 increases. When IC8 increases to >0.6V, T9 turns on and plays the role of shunting.In this way, the excessive burden of T8 is relieved, and the variation range of IC8 is narrowed.